00:02
All right, so in this problem, we already know that we have two capacitors, c1, c2, and we did four tests.
00:14
So we did two individuals, and we also did a parallel connected one and a series connected one.
00:27
So we have the four tests.
00:29
And each test gives us the energy from the smallest to the largest.
00:34
We have 75 microchyls and 100 microjoules, 300 microjoules, and 400.
00:47
So but we do not know which one has the smallest one or the largest one.
00:53
But we from this setup we actually can see that if the c1, c2, they are in parallel, basically the combined capacitance c will be so parallel cp equal to c1, c2, divided by c1 plus c2.
01:10
And this value actually, it is smaller than c1 and c2.
01:17
I'm sorry.
01:18
This is series.
01:21
C series.
01:25
So if they are connected in series, then they have combined capacitance given this expression.
01:30
And it is smaller than c1, c2...