00:01
In this exercise, we have the system shown here in the figure on the left that's composed by two masses, m1 that has a mass of 15 kilograms, and m2 that has a mass of 20 kilograms, that are connected by a string that passes through a pulley that has a radius of 0 .25 meters and a moment of inertia i.
00:27
And the acceleration of the system is two meters per second downwards for mass 2 and upwards from s1.
00:38
And our goal in question a is to find the tensions t1 and t2 in the string.
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So in order to do that, i'm going to write the force equation for both m1 and m2.
00:58
So notice that acting upon m1 we have a gravitational force that has two components.
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One of them is in the direction of motion, and the second one is perpendicular to the direction of motion.
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Notice that the pull is not moving in the direction perpendicularly to the motion.
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So this means that i'm only going to care about the forces that are that.
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That are exerted on the direction of motion.
01:31
So for m1, we have the force that is pulling the block upwards is t1, and the one that's pushing it down is mg times sine of theta.
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Theta is this angle here, which is equal to 37 degrees.
01:55
And this is equal to m times a.
02:00
So t1 is equal to m, actually here we should have m1.
02:06
So this is m1 times a plus g times sine of theta.
02:13
So this is 15 kilograms times a, which is 2 meters per second squared, plus g, which is 9 .8 meters per second squared, times the sign of 37.
02:30
And this is equal to 118 .5 newton.
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Then we have to find t2.
02:41
Notice that the forces that act on t2 are just the gravitational force downwards and the tension force to 2...