00:01
Hi, in the given problem here, there are two blocks on a horizontal platform.
00:11
This is block b and this is block a.
00:19
These two blocks are joined with the help of a light horizontal string.
00:27
A force f is applied on the larger block, attention, the string will be t shown.
00:41
Shown like this.
00:43
Mass of the block a is given as 15 .0 kilogram while mass of block b is missing.
00:54
So let it be m only.
00:57
The force applied on block a is given as 60 .0 newton under which the block a moves a distance of 18 .0 meters.
01:12
In the first 5 .00 seconds.
01:18
So in the first part of the problem, considering the motion of block a.
01:28
So for motion of block a, its initial speed, vi is 0.
01:40
Distance traveled by it is 18 .0 meter in a time t is equal to 5 .00 second.
01:50
So using second equation of motion which says s is equal to v i t plus half a t square it becomes for s this is 18 is equal to 0 as initial speed was 0 plus half a into the square of t means square of 5 so it comes out to be 25a by 2.
02:22
Hence, acceleration of this block a will come out to be a is equal to 18 into 2 divided by 25.
02:42
Means this is 36 by 25 meter per second square from here...