00:01
All right, we've got two blocks, a and b.
00:07
So we'll draw them here.
00:11
They're connected with a rope.
00:18
We'll call this a.
00:20
We'll call this b.
00:22
Block a is 15 kilograms.
00:29
Block b has a mass of m.
00:32
I'm going to call that m sub b, and i'll call this m sub a.
00:38
A force of 60 newton's is applied to block a.
00:57
The amount of time is five seconds.
01:04
And block a moves, and therefore a block b would also have to move, 18 meters to the right.
01:20
Okay? well, i'm going to answer part b first.
01:30
Force, the net force, is the mass times the acceleration.
01:44
But it's moving both blocks because they're connected together in a rope.
01:59
So it's moving both of the masses with an acceleration.
02:06
We don't really know the acceleration initially, but x is going to be x0.
02:16
Plus v0 t plus one half a t squared.
02:26
Since x0 is zero and since the velocity initially is zero, then a is going to be 2x over t squared.
02:43
So where i see a up here, i can just erase it.
02:50
And write 2x over t squared.
03:01
T squared would be 25.
03:06
Okay, so i solved this for m sub b...