00:01
All right, we have a drawing.
00:15
Looks like this.
00:19
Okay, m1 is greater than m2.
00:28
The table's frictionless.
00:42
P is the contact force between the two blocks.
01:06
Okay, so there's the free body diagram.
01:15
What's the net force on the system? well, the net force on the system is just f, as you can see above.
01:37
C is the net force on m1.
01:42
Well, force net on m1 is going to be f minus p.
01:57
Net force on m2 is just p.
02:08
The x component of newton's second law.
02:13
So for m1, f minus p equals m1a.
02:23
And then p equals m2a.
02:40
So i need to solve for a and p.
02:45
Well, in the second one, a equals p over m2.
02:52
So substituting that into the first, f minus p equals m1, p over m2 so f equals just rearranging this m1 over m2 plus one times p um um um 2 over m2 plus 1 times p okay good so i need a and p in terms of m and f so wait a minute p is therefore going to be f over m1 over m2 plus 1.
03:51
Okay, now i also need a...