Question
Two bodies have their moments of inertia la $2 I$ respectively about their axis of rotation. If their kinetic energies of rotation are equal, their angular momenta will be in the ratio(a) $1: 2$(b) $\sqrt{2}: 1$(c) $1: \sqrt{2}$(d) $2: 1$
Step 1
We know that kinetic energy of rotation is given by $\frac{1}{2}I\omega^2$. So, we can write the equation as $\frac{1}{2}I_1\omega_1^2 = \frac{1}{2}I_2\omega_2^2$. Show more…
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Two bodies with moment of inertia $I_{1}$ and $I_{2}\left(I_{1}>I_{2}\right)$ have equal angular momentum. If the $\mathrm{KE}$ of rotation is $E_{1}$ and $E_{2}$, then (a) $E_{1}>E_{2}$ (b) $E_{1}<E_{2}$ (c) $E_{1}=E_{2}$ (d) None of these
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