Two capacitors C1=5.2 μF and 0.1 μF and c2=12.2 μF are joined (i) In series (ii) In parallel. Fi

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Two capacitors C1=5.2 μF and 0.1 μF and c2=12.2 μF are...

Two capacitors $C_{1}=5.2 \mu F$ and $0.1 \mu F$ and $c_{2}=12.2 \mu F$ are joined (i) In series (ii) In parallel. Find the net capacitance in these two cases.
(A) $2.8 \%, 1.23 \%$
(B) $3.6 \%, 1.31 \%$
(C) $3.4 \%, 1.3 \%$
(D) $3.9 \%, 1.15 \%$

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Key Concepts

Series Connection of Capacitors

In a series configuration, capacitors are connected end-to-end so that the same charge passes through each capacitor. The total or equivalent capacitance is found by taking the reciprocal of the sum of reciprocals of the individual capacitances. This results in a smaller net capacitance compared to any single capacitor in the series.

Capacitance

Capacitance is a measure of a capacitor’s ability to store electrical charge per unit voltage. It is defined by the relationship Q = CV, where Q represents the stored charge, C is the capacitance, and V is the voltage. It is measured in farads (F), and practical circuits often use microfarads (?F) for component values.

Parallel Connection of Capacitors

When capacitors are connected in parallel, their corresponding terminals are connected together, and they all share the same voltage across them. The equivalent capacitance is simply the sum of the individual capacitances. This arrangement increases the overall capacitance, allowing for greater charge storage at a given voltage.

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