00:01
In this question, we have two capacitors, c1 and c2.
00:05
So when they are connected in parallel, so the equivalent capacitance is given to be cp.
00:22
Then if they are connected in series, the equivalent capacitance is c.
00:30
So we want to find c1 and c2.
00:35
So to do this question, so in parallel arrangements, we have cp equals to c1 plus c2, and then in series arrangement, 1 over c is equal to 1 over c1 plus 1 over c2.
00:57
So to solve for c1 and c2, so we need to use the two equations.
01:10
So from 2, we have c1 is a very much.
01:19
Equal to c1, c2, c1, c2, devip by c1 plus c2.
01:32
And then if you look at equation 1, you can say c1, c2, divide i, cp.
01:43
And then also from 1, we have c1 equals to c2, c2, c1 equals to cp minus c2, so we have cp times c equals to cp minus c2 times c2...