00:01
Okay, so we're doing chapter 29, problem 17.
00:06
So, part a.
00:08
Well, let's draw this figure first.
00:10
We have a wire with the current i in the right direction.
00:18
And we have two closed loops here.
00:20
So here's one loop in a circle is a, and then we have a rectangular loop.
00:27
A rectangular loop here we call c.
00:32
Okay.
00:32
So it says find the direction clockwise and counterclockwise of the current induced in each loop i is steadily decreasing.
00:46
So that means d .i.
00:49
D .t is less than zero.
00:51
So current is decreasing.
00:55
So first we got to figure out what direction magnetic field is in.
01:03
Okay? so we have a current flow.
01:09
This way, using the right hand rule, we can see that our magnetic field is going around like this, which means it is into the page here, out of the page here.
01:31
Okay? so if d .i.
01:38
D .t is less than zero, and b is proportional to i, we know that d .b.
01:47
D .t.
01:48
Is also less than zero.
01:49
Which means the magnitude of our magnetic field is decreasing okay so we're looking at loop a is into the page the field but it's also decreasing so it's getting less into the page which means to oppose the change in the field or the change in flux through this loop, it would induce a current that would produce a b field more into the page.
02:33
Since it's into the page and decreasing, using linses law, we need to induce a current that would produce a b field into the page.
02:44
So using the right hand rule again, we see that a induced current has to be clockwise.
03:00
So now if we're going to c, the only difference is we're out of the page.
03:06
C is out of the page.
03:08
The b field is...