00:01
For this exercise, we have two monochromatic light sources, one yellow, whose wavelength is 580 nanometers, and one violet, whose wavelength is 425 nanometers.
00:19
And we also have a metal whose threshold frequency, that is the minimum frequency of light, necessary to remove an electron from the surface is 6 .2 times 10 to the 14th thirds.
00:43
And then in the first question we're asked if both monochromatic light sources are able to to remove electrons from the metal.
00:59
So in order to do that, we all you have to do is to see if the frequency of the two monochromatic light sources is bigger or smaller than the threshold frequency.
01:09
If it's bigger, then they can remove electrons.
01:11
If it's smaller, then they cannot.
01:14
So the frequency of the yellow source is going to be the speed of light over the wavelength of the yellow source.
01:23
And this is 3 times 10 to the 8th over.
01:29
Now we have to convert the frequency lambda to meters, so 580 nanometers is the same as 5 .8 times 10 to the minus 7 meters.
01:48
The velocity is in meters per second.
01:51
And here we have 5 .2 times 10 to the 14th hertz, and the violet source has a frequency that can be calculated similarly.
02:07
So it's going to be the velocity, the speed of light over 4 .25 times 10 to the minus 7 hertz...