00:01
So we have three metal plates and two of them are connected to ground like this.
00:08
And then we stick one in the middle.
00:11
So this is d and 2d.
00:14
And we know the charge on the middle one is q.
00:18
So i'm going to say this is q1 and q2, where they're both negative since the middle one is positive.
00:25
So it's really minus, but i'll account for that at the end.
00:30
And we have two capacitors, c1 and c2.
00:35
Which are going to be a times epsilon knot over d, and the same, but with double the separation distance.
00:46
So we know, first of all, that the total charge is the sum of q1 and q2, and again, we're working in magnitudes here since q1 and q2 are negative.
01:00
We also know that the charge for any capacitor is the capacitance times the voltage.
01:06
So we can say that the voltage is charge over capacitance.
01:15
And now i'll call this v1 and v2.
01:18
We know the potential for either capacitor has to be the same since they're both connected to ground, right? so i can substitute in q and c.
01:34
This is q1 over c1, and this is q2 over c1, and this is q2 over c...