Two metal spheres of radius 5.0 cm carry net charges of +1.0 μC and +0.2 μC . (a) What (approxi

step 1 The force is given by k, Q1, Q2 over R squared, K is 9 times 10 to the 9 times Q1 is 10 to the m

Two metal spheres of radius 5.0 cm carry net charges of...

Two metal spheres of radius $5.0 \mathrm{~cm}$ carry net charges of $+1.0 \mu \mathrm{C}$ and $+0.2 \mu \mathrm{C} .$ (a) What (approximately) is the magnitude of the electrical repulsion on either sphere when their centers are $1.00 \mathrm{~m}$ apart? (b) Why cannot Coulomb's law be used to find the force of repulsion when their centers are $12 \mathrm{~cm}$ apart? (c) Would the actual force be larger or smaller than the result of using Coulomb's law with $r=12 \mathrm{~cm}$ ? Explain.

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Key Concepts

Charge Distribution on Conductors

In conductive objects, charges reside on the surfaces and are free to redistribute, especially when the objects are close to each other. This redistribution can lead to deviations from the idealized results predicted by Coulomb's law, making it important to consider the actual geometry and proximity of the charged bodies when they are not well separated.

Point Charge Model

The point charge approximation assumes that all of the charge on an object is concentrated at its center, which is a valid simplification when the separation between objects is much larger than their dimensions. This concept is crucial in understanding the conditions under which Coulomb's law can be correctly applied.

Coulomb's Law

This law defines the electrostatic force between two point charges as being directly proportional to the product of their charges and inversely proportional to the square of the distance between them. It is fundamental in electrostatics for calculating forces when the objects can be approximated as point sources of charge.

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