Question
Two parallel and opposite forces each $5000 \mathrm{~N}$ are applied tangentially to the upper and lower faces of a cubical metal block of side $25 \mathrm{~cm}$. The angle of shear is (The shear modulus of the metal is $80 \mathrm{GPa}$.)(a) $10^{-4} \mathrm{rad}$(b) $10^{-5} \mathrm{rad}$(c) $10^{-6} \mathrm{rad}$(d) $10^{-7} \mathrm{rad}$
Step 1
The side of the cube is given as $25 \mathrm{~cm}$, which is $25 \times 10^{-2} \mathrm{~m}$. The cross-sectional area $A$ is then the square of the side length, which is $(25 \times 10^{-2})^2 = 6.25 \times 10^{-4} \mathrm{~m}^2$. Show more…
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Two parallel and opposite forces each $4000 \mathrm{~N}$ are applied tangentially to the upper and lower faces of a cubical metal block of side $20 \mathrm{~cm} .$ The angle of shear is: (The shear modulus of the metal is $80 \mathrm{GPa}$.) (a) $1.25 \times 10^{-4} \mathrm{rad}$ (b) $2.25 \times 10^{-6} \mathrm{rad}$ (c) $1.25 \times 10^{-6} \mathrm{rad}$ (d) $1.25 \times 10^{-5} \mathrm{rad}$
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Two parallel oppositely directed forces, each $4000 \mathrm{~N}$, are applied tangentially to the upper and lower faces of a cubical metal block $25 \mathrm{~cm}$ on a side. Find the angle of shear and the displacement of the upper surface relative to the lower surface. The shear modulus for the metal is 80 GPa.
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