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Hi friends, this is a problem based on the concept of force of interaction between two charges is given by kulum s.
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K.
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K.
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K.
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K.
00:38
K, k, k, k, k, k, k, k, k, k, k, k, k, k2, r1, 2 square, 9 into 10 to the power 9, 7, 7, 2, 7, 7, 2, 7.
00:57
10 to the power minus 6 18 into 10 to the power minus 6 upon d square see the diagram as given this is q1 this is q2 this is the distance d electric field is in this direction so q1 e will be in this direction because it is negative this is minus 18 micropoleum so it will be q2e so net force on q1 e net 1 minus q1 e plus f1 2 q1 e is given q1 is minus 7 micropulum and electric feet is 2500 1 .134 upon d square so you can write net force on q1 will be minus 0 .0 175 plus 1 .134 upon d squared newton.
02:37
Acceleration of q1, a1 will be f net 1 upon mass.
02:53
So net acceleration, sorry, acceleration of q1 and its mass is 1 .4 into 10 to the power minus 5 ag...