00:02
In this question, we have two particles that exist in a uniform electric field, and we are given the masses and charges of those particles, and we know that when they are released from rest, they maintain a constant separation.
00:23
And we want to find out what is that separation.
00:27
So let's start.
00:29
We're going to draw in...actually, you know something, since i almost never get to use yellow, we're going to draw our electric field in yellow.
00:37
So i'm going to allow my electric field to exist pointing to the right, because it does say positive x direction.
00:48
And we're then going to have charge 1, it says, is to the left of charge 2.
00:55
So i'm going to put my negative q1 here, and then i'm going to draw my positive q2 over here.
01:15
And we are going to specify that they are...actually, i want a different color for that.
01:22
We're going to specify that they are separated by a distance d.
01:29
So each of these charges is going to feel two forces.
01:33
One from the electric field.
01:36
I'm going to change my mind, we're going to use orange to worry about electric field things.
01:43
And they will each also feel a force from the other charge.
01:50
So, keeping in mind that the direction of an electric field is determined by the force that a positive charge feels, that tells me that the force of the electric field on charge 1 is going to point to the left.
02:06
And the force of the electric field on charge 2 will point to the right.
02:13
Charge 1 is going to be attracted to charge 2, so it will feel forced to the right.
02:22
And charge 2, similarly, will feel attracted to charge 1, so it's going to feel a pull back to the left.
02:39
So, here's a key concept.
02:43
Is that two...let's try writing this a little bit more legibly.
02:48
So, to maintain d, they must have the same magnitude and direction of their acceleration upon release.
03:19
Because that means that they will gain velocity in precisely the same way.
03:25
And that's what will allow them to maintain the distance.
03:29
So, we need to be able to say that the acceleration of charge 1 will be equal to the net force on charge 1 divided by its mass.
03:40
The acceleration of charge 2 will be the net force on charge 2 divided by its mass.
03:47
And then we will be able to set those two accelerations equal to each other.
03:56
One thing i'm going to do before i dive into that.
04:01
I'm going to go ahead, since by newton's third law, f12 equals f21, i'm going to go ahead and just calculate that right now.
04:14
With k, or you could use 1 over 4 pi epsilon naught, but kq1q2 over d squared.
04:23
So, we'll do our 9 times 10 to the 9th.
04:25
And then of course, using coulomb's law, we only ever use the positive values.
04:37
Oops, that should be 10 to the negative 6th, sorry.
04:40
We only ever use the positive values of our charges, the absolute values.
04:44
We let the signs determine the relative directions of those forces, left, right, etc.
04:54
And so, we are able to say that the force between charges 1 and 2, oh go figure, i didn't actually, oh yeah i did, there we go, sorry i just had to find it.
05:12
1 .134 over d squared.
05:17
And we will apply that appropriately for each one in determining its net force.
05:24
So let's, let's go do acceleration of charge 1.
05:29
It's going to be the net force on 1 divided by the mass of 1.
05:34
So i'm going to write it as 1 over the mass of charge 1, which is 1 .4 times 10 to the minus 5th kilograms.
05:45
And then it is going to feel in the positive.
05:52
Oh, i just realized i'm totally, hang on, i like my color coding guys.
05:56
I'm going to fix this real quick...