The vitreous humor, a transparent, gelatinous fluid that fills most of the eyeball, has an index of refraction of 1.34. Visible light ranges in wavelength from 380 nm (violet) to 750 nm (red), as measured in air. This light travels through the vitreous humor and strikes the rods and cones at the surface of the retina. What are the ranges of (a) the wavelength, (b) the frequency, and (c) the speed of the light just as it approaches the retina within the vitreous humor?

## Discussion

## Video Transcript

this problem. We have two mirrors that are perpendicular to each other and light strikes this first mirror and bounces off back. And then it's done. The problem is asked for what? Angle off incident at the first mirror. Will the rail strike midpoint of the second mirror, which is 28 sending me to the law. So then we will find this angle. And from this angle, this is normal. Will find this angle this angle off incident. Hey, um, So we confined far this angle, which is saying that can be found Or let me call this fi. So let's call this fi. So this is Fi. So this is Fi. So this is after this is oh, fight Here is the fi So then this will be fine. So sorry about that mess. And, uh so this is fire. So Tang Fei will be equal to 14 centimeter because off the midpoint and then the 11 it strikes the from here to here From here to here that's 11 on from here to here. That's 14. So off 11.5, If we divide this and then sold for If I then the five you get here is 50.6 degrees, and then we confined angle off reflection from here. Just objecting. This, um, this are We can subtract a five from 90 degrees and then, uh, we get this angle 39.4, and then we know this angle of reflection should equal to angle off incident for this case, off playing mirrors. And so the angle off incident is denying 0.4 degrees. End off the problem. Thank you.

## Recommended Questions