00:01
This question, we have this configuration as shown in the plot.
00:04
We have a positive charge of 2 .4 nano -nacholon.
00:11
And we have a negative charge that is negative 6 .5 nanocolon.
00:19
And we have point a and point b as can be seen from the graph.
00:23
So we want to know the potential between a and the potential at point b and the potential at point b and the potential difference between some parts.
00:32
And from that potential difference, what we can find is work done on a chart when it moves from b to a.
00:39
So in section three, in section three of chapter 18, what we learn is that the potential of different, at a certain point, there's a superposition of the potential caused by all different sources.
00:58
So say the potential at a, it will be the sum of the potential caused by both the positive charge and the negative charge.
01:08
So i have va equals kq1 over r, ra, cost by 1.
01:18
Because this is just a formula for the potential to a single charge, plus kq2 over r, a caused by 2.
01:29
Okay, so k is 9 times 10 to the 9th.
01:35
Meter square, column square.
01:38
R is the r1, r1 and r82 are actually the same.
01:42
It's the same distance as 0 .05 meter...