00:01
I am drawing two spheres.
00:09
I wanted them to be two different colors.
00:12
One of them is larger than the other.
00:21
This one has a mass m, and this one has a mass 2m.
00:39
And the distance between their centers initially is 12r.
00:59
So we're going to consider them colliding.
01:08
So we're going to use conservation of linear momentum, and we're considering when they collide.
01:26
So at collision, then the distance between them is going to be 4r when they collide.
01:43
3r plus 1r is 4r.
01:46
So they're initially at rest.
01:53
So m1 v1 plus m2 v2 initial, these are zero.
02:11
So m1 v1 final plus m2 v2 final would be zero.
02:29
So, therefore, m1 v1 at collision is the opposite of m2 v2 at collision.
02:49
So solve for v1 in terms of v2.
03:05
So we know that m1 is just m.
03:13
And we know that m2 is 2m.
03:20
So v1 is going to be negative 2 v2.
03:28
So i've actually been answering b.
03:32
The answer to a is linear momentum and energy, conservation of those.
03:46
C, okay, kinetic energy initial, plus potential energy initial, equals kinetic energy final plus potential energy final.
04:08
Initially, they're not moving.
04:13
The potential energy initial is m1, m2.
04:28
I forgot g.
04:29
G, m2, over r.
04:36
But initially, their distance apart is 12r.
04:44
Equals kinetic energy final.
04:49
One half.
04:52
Now they're both going to have kinetic energy in the end.
04:56
One half m1 v1 squared plus one half m2 v2 squared minus g m1m2 over the radius at collision, which is 4r.
05:19
Now, m1 is m, and m2 is 2m.
05:27
So, negative g m 2m over 12r equals 1 1ā2m, equals 1 half m v1 squared plus 1 half 2m v2 squared, minus g m 2m over 4r.
06:03
Now, we need to solve this for v1 also.
06:08
So i'm going to add this to both sides, and that's going to give me.
06:19
Well, first of all, i can factor out g, m squared, over r...