00:01
All right, we've got two subway stops that are 1 ,100 meters away.
00:16
Okay.
00:18
If the subway train accelerates, oops, 1 .2 meters per second squared through the first half of the distance, and then decelerates through the second half, okay, well, what's the time? time.
00:55
D over 2 would be x initial which is 0 plus v initial t which is 0 plus one half a t squared.
01:14
And so this is actually only half the time.
01:22
So i'm going to write it as t sub 1.
01:25
That's half of the total time.
01:28
So these cancel out.
01:34
The time for the first half is going to be the square root of d over a.
01:47
So putting this in a calculator, d equals 1 ,100, a equals 1 .2, square root of d over a is is 30 .3 seconds.
02:07
Let me look at significant digits.
02:09
So it's 30 seconds.
02:11
We multiply that by two.
02:15
Actually is going to get us to 61.
02:17
So the total time is 61 seconds, because it's twice as much as this.
02:24
Ok...