00:02
Okay, in this problem, we have two vectors.
00:06
We have vector a and vector b.
00:10
And we're told that when we add the two vectors together, we get some distance, and we subtract the vectors.
00:23
We get some other distance.
00:26
So that's d plus and d minus.
00:29
And we're told that d, when we add them, is n times bigger than d minus.
00:38
And the question is, what's the angle that makes that happen? now, normally with vectors, i would want to find x and y components, but because we don't know what that angle is, it's really hard to break it into normal right triangles.
00:58
And so really, the only rule that i know that helps us with this is the law of cosines.
01:04
And that's the distance of the opposite angle.
01:08
So if this is the angle, it's the distance of that line, is equal to a squared plus b squared minus 2ab cosine theta.
01:21
And notice when theta is 90, that cosine term goes to zero, and that turns into the pythagram theorem.
01:27
So the pythagrin theorem is just a subset of the law of cosines.
01:34
We know though that a is equal to b and so i'm going to use the capital letters that i was using earlier so d squared is equal to a squared technically the magnitude of a plus a squared because b is the same thing as a times 2 times a times a times the cosine of theta well obviously that is a squared also and so d squared is equal to 2 a squared times one minus cosine theta if we simplify that equation.
02:13
So now i'm going to go ahead and treat this as just d and i'm just going to call this one n times d or d is the smaller distance and d is the larger distance and so i know that and in fact instead of using lowercase let me use a capital d and a capital d...