Question
Two vectors $\vec{A}$ and $\vec{B}$ are such that $\vec{A}+\vec{B}=\vec{C}$ and $A^{2}+B^{2}=C^{2}$If $\theta$ is the angle between positive direction of $\vec{A}$ and $\vec{B}$ then the correct statement is (B) $\theta=\frac{2 \pi}{3}$(A) $\theta=\pi$(C) $\theta=0$(D) $\theta=\frac{\pi}{2}$
Step 1
We know that the magnitude of $\vec{C}$, the resultant of $\vec{A}$ and $\vec{B}$, is given by the formula $C=\sqrt{A^{2}+B^{2}+2AB\cos\theta}$. Show more…
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Two vectors $\vec{A}$ and $\vec{B}$ are such that $\vec{A}+\vec{B}=\vec{C}$ and $A^{2}+B^{2}=C^{2}$. If $\theta$ is the angle between positive directions of $\vec{A}$ and $\vec{B}$ then mark the correct alternative (a) $\theta=0^{\circ}$ (b) $\theta=\frac{\pi}{2}$ (c) $\theta=\frac{2 \pi}{3}$ (d) $\theta=\pi$
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If vectors $\vec{A}$ and $\vec{B}$ have an angle $\theta$ between them, then value of $|\hat{A}-\hat{B}|$ will be (a) $2 \cos \frac{\theta}{2}$ (b) $2 \tan \frac{\theta}{2}$ (c) $2 \sin \frac{\theta}{2}$ (d) Nonc
Vectors and Scalars
Section B
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