00:01
Okay, so we know the magnetic fields can be equal to mu0 i over 2 pi r.
00:06
So muo is the permeability constant, okay, which is equal to 4 pi times 10 to the power of negative tesla times meter per ampere, okay? and we have bp, which is the magnetic field at point p, is equal to negative mu zero i .1 over 2 pi i .1 plus mu zero i2 over 2 pi i.
00:30
2 pi r2.
00:32
And then we have mu 0 over 2 pi times i1 over r1 plus i2 over r2.
00:41
And all this is because the current is flows toward right in this case.
00:46
So we need to use negative sign here.
00:50
And then we know that i1 is equal to 10 ampere, which is the current that was flowed over right.
00:58
And the current that flows upward is equal to 12 ampere.
01:03
And we know the vertical distance is given as an 8 centimeter, which is 0 .08 meter.
01:08
And the horizontal distance is 15 centimeter, which is 0 .15 meter.
01:16
So therefore, we can plug back into the equation.
01:19
Then we have the magnetic field at point p is equal to 4 pi times 10 to the power of negative 7, tesla times meter per ampere, over 2 pi and then times i forgot a netics sign here sorry about that and then times 10 ampere over 0 .08 meter plus 12 .0 ampere over 0 .15 meter and this will give us the magnetic field at point p is about negative 4 .1 times 10 to the power of negative tesla, which is negative 41, microtesla.
02:34
And since it's negative, that means the direction of the magnetic field at point p is into the page.
02:43
Because we can use the right -hand rule to examine it, okay? and if you use the right -hand rules, you'll find out the direction for such values is into the page.
02:59
So therefore, the magnetic view at point q should be in the opposite direction...