00:01
In this problem, we're going to talk about the energy levels of the hydrogen atom.
00:04
And what we need to remember is that given that the principal quantum number of the hydrogen atom is n, that is the energy level is n, then the energy of that energy level is minus 13 .6 electron volts divided by n square.
00:21
Also, we need to remember that if the atom has a principal quantum number and its orbital quantum number can range from 0 to n minus 1.
00:32
And the orbital quantum number is related to the orbital angular momentum, such that the magnitude of the angular momentum is a square root of the orbital quantum number times the orbital quantum number plus 1 times h4.
00:47
And the magnetic quantum number ranges from minus l to plus l in steps of 1, such that the third component of the magnetic, i'm sorry, the third component of the orbital angle.
01:05
Angular elementum is equal to m hbaw.
01:10
Okay, so in this problem we have a hydrogen atom in the second excited state.
01:16
The second excited state means the n equals three quantum state and that is because n equals 1 is equal to the ground state and equals 2 is the first excited state and then n equals 3 is the second excited state.
01:36
In question 8 you have to find the energy so if 3 is equal to minus 13 .3 electron volts divided by 3 squared, and this is just minus 1 .51 electron.
01:51
Then in question b, we have to find the maximum value of the angular momentum...