Recall that $1 \mathrm{~atm} = 760 \mathrm{~torr}$.
For situation (a), the atmospheric pressure is $1.05 \mathrm{~atm}$. To convert this to torr, we multiply by 760 torr/atm:
\[1.05 \mathrm{~atm} \times 760 \mathrm{~torr/atm} = 798 \mathrm{~torr}\]
For situation
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