Question
Unpolarized light is incident on a system of three polarizers. The second polarizer is oriented at an angle of $30.0^{\circ}$ with respect to the first and the third is oriented at an angle of $45.0^{\circ}$ with respect to the first. If the light that emerges from the system has an intensity of $23.0 \mathrm{W} / \mathrm{m}^{2},$ what is the intensity of the incident light?
Step 1
Mathematically, this is expressed as $I = I_0 \cos^2(\theta)$, where $I$ is the final intensity, $I_0$ is the initial intensity, and $\theta$ is the angle between the light's initial polarization direction and the axis of the polarizer. Show more…
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Unpolarized light is incident on a system of three ideal polarizers. The second polarizer is oriented at an angle of $30.0^{\circ}$ with respect to the first, and the third is oriented at an angle of $45.0^{\circ}$ with respect to the first. If the light that emerges from the system has an intensity of $23.0 \mathrm{W} / \mathrm{m}^{2},$ what is the intensity of the incident light?
Unpolarized light is incident on a system of three ideal polarizers. The second polarizer is oriented at an angle of 30.0° with respect to the first, and the third is oriented at an angle of 45.0° with respect to the first. If the light that emerges from the system has an intensity of 31.9 W/m2, what is the intensity of the incident light? (W/m2)
*Unpolarized light passes through three polarizers. The second makes an angle of 25° relative to the first, and the third makes an angle of 45° relative to the first. The intensity of light measured after the third polarizer is 40 ${W} / {m}^{2}$ . Determine the intensity of the unpolarized light incident on the first polarizer.
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