00:01
So for this problem, we're supposed to find the number of atoms of nitrogen, carbon, oxygen, and hydrogen, and some quantity of urea.
00:08
So we know that we are dealing with 1 .68 times 10 to be 4 grams of urea.
00:16
So the number one step we have to do is you have to calculate the molar mass of urea, so we can then convert that into moles.
00:22
And so that is just going to be we have two molecules or two nitrogen atoms, and the amu for nitrogen is 14 .01.
00:33
We have four hydrogen atoms, which is 1 .008.
00:38
We have a carbon atom, and then we have an oxygen atom.
00:44
So when we add all those together, we get that the molar mass, 60 .06 grams per mole.
00:53
And so then we can convert that into something a lot more useful for us.
00:57
So now we have 1 .68 times 10 to the 4 grams of urea.
01:03
We can then multiply or divide by the molar mass, so we get moles of urea, and then multiply by avogadro's number.
01:22
So this will get us the number of atoms of both carbon as well as oxygen...