Use (4.18) to show that for very high-energy "spinless" electron-muon scattering,
$$
\left.\frac{d \sigma}{d \Omega}\right|_{c m}=\frac{\alpha^{2}}{4 s}\left(\frac{3+\cos \theta}{1-\cos \theta}\right)^{2}
$$
where $\theta$ is the scattering angle and $\alpha=e^{2} / 4 \pi .$ Neglect the particle masses.