Use (4.18) to show that for very high-energy "spinless" electron-muon scattering.
$$
\left.\frac{d \sigma}{d \Omega}\right|_{c m}=\frac{\alpha^2}{4 s}\left(\frac{3+\cos \theta}{1-\cos \theta}\right)^2
$$
where $\theta$ is the scattering angle and $\alpha=e^2 / 4 \pi$. Neglect the particle masses.