00:01
We want to find the area of the region enclosed by these two functions.
00:04
The first one in blue, y equals 3x squared minus 2x, and the second in green.
00:09
Y equals x to the 3 minus 3x plus 4.
00:13
So if we do a quick graph using a graph in calculator, at first glance it looks like there's one region over here.
00:22
Because at first glance it looks like there's two intersection points.
00:25
But if we actually zoom out, we find that there's a third intersection point, which happens at a higher x value.
00:34
So we actually have two regions, the first one being down here, which we saw on the first slide, and the second region is this tiny sliver that goes over here.
00:52
So the total area is actually going to be the sum of two areas, which will solve independently.
00:57
So i'll write this as area is equal to area 1 plus area, so we're going to figure out area 1 and area 2 separately.
01:11
So area 1 i drew it in green, and area, i mean in red, and area 2, i drew in black.
01:19
So let's solve these two areas separately.
01:23
Area 1 is equal to, we're going to do an integral.
01:28
So let's look at our first picture, since it's a bit more clear.
01:32
Our first x value is going to be negative 1 .115, and our upper value is going to be.
01:39
To be 1 .254.
01:42
So let's write those in.
01:45
Negative 1 .115 to 1 .254.
01:54
And it's going to be the upper function minus the lower function.
01:57
Here the upper function is the green one and the lower function is the blue one.
02:02
So we're going to subtract those.
02:08
The green function, x cubed minus 3x plus 4, minus the blue function, 3x squared minus 2x dx.
02:27
Okay, of course we can simplify this a little bit.
02:34
We have an x cubed, we have minus 3x squared, we have a minus x and then we have a plus 4 dx.
02:45
So we can carry out this integral by doing the antiderivative, 1 fourth x to the 4 minus x cubed...