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# Use a graph to give a rough estimate of the area of the region that lies beneath the given curve. Then find the exact area.$y = \sqrt[3]{x}$, $0 \le x \le 27$

## $=60.75$

Integrals

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### Video Transcript

Okay. We know our graph would look a little something like this. So our area would be from 0 to 27 cube root of ax D backs. I remember the expert increases by one. So increases from 1/3 to 4/3. Divide by the new exponents. Substitute 243 to about that floor.

Integrals

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