00:02
Okay, in this problem we're asked to look at the balmer, at a line in the balmer series, specifically that for the gamma line in hydrogen.
00:10
And for that particular line, we're asked to find the wavelength, frequency, and energy of the photon corresponding to this line.
00:17
So recall the equation, the bomber series, which gives us the wavelength in terms of this r value and a index for a lower and upper level, r is 1 .097, e.
00:31
The negative 7 inverse meters.
00:37
And recall, for the h gamma, the h gamma line, the lower value is n equals 2.
00:45
The upper value is n equals 5.
00:49
And the text discusses the convention for how these are determined.
00:53
The upper level increases with the greek letter.
00:58
So h alpha would be 3, beta, 4, gamma is 5.
01:04
That's how we get to these particular.
01:07
Indices.
01:10
So with that said, we can jump in, plug these values in, and find this lambda.
01:17
So as i mentioned, you just plug some numbers in.
01:23
So for the lower, we have one over the lower, 2 squared, minus one over the upper, 5 squared.
01:32
All this is inverse.
01:37
And after plugging these numbers in, plugging in our value for r computing, we are left with a value of 434 nanometers...