00:03
Problem number 79, so starting with part a.
00:08
Let me write the reaction first to h .i.
00:18
Both the reactants and product are in gaseous state.
00:22
First of all, we need to calculate the gips free change in gip's free energy.
00:28
So the formula for change in gip's free energy is delta g0 equals delta g value of product minus the delta g value of reactants.
00:51
Substituting the numbers, we have 2 multiplied with 1 .30 minus 0 plus 19 .37.
01:07
So the delta g value or change in giprity is negative 16 .77 kilojoules.
01:17
Just remember the formula of change in gibbs free energy.
01:20
This formula will be used throughout the question.
01:24
There's another form.
01:25
Which will be used throughout the quotient that is also delta g not equals negative r t k equilibrium we need to find the equilibrium value that is k equilibrium so k e k will be equal to e raise to power negative delta g divided by r t remember these two formula these two formula will also be used throughout decursion.
02:05
So, substituting the values, we have e raised to power negative 16 .77, multiplied with 10 raised to power 3, joules divided by 8 .3 .34, multiplied with temperature, 298, e will be equal to 6 .78, 6 .78.
02:35
6 .78...