00:01
Okay, we've got a few reactions that we need to show the mechanism, or at least the steps using curved arrow formalism for...
00:13
I'm only going to draw the lone pairs that are absolutely necessary, but we're told that this is going to go to cyclohexanone with cl minus.
00:25
Okay, so i know that i need to form a new bond between oxygen and carbon, because i have a double bond.
00:32
Bond over here.
00:33
So i'm going to use this lone pair, drawing an arrow from that lone pair to the double bond to create a new bond.
00:39
I also know that i need to break this carbon chlorine bond.
00:42
So i'm going to draw an arrow from that bond to the chlorine to signify it leaving.
00:49
Right.
00:50
So that's where i'm going with this.
00:52
Okay.
00:54
Now we've got what looks to be a radical reaction.
00:58
And we've got br2.
01:03
One tricky thing is that.
01:05
That when you've got these radical reactions involving br2, it's always best to draw your br2 like this, because you need to have this bond to be able to break and form bonds with it.
01:17
And we know that this is going to basically brominate this and leave behind a bromine radical.
01:24
That's what they told us.
01:25
Okay, so we know we need to form a carbon bromine bond via radical mechanism.
01:31
So it's going to use a half -head arrow...