Question
Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function.$$g(x)=\int_{1}^{x} \frac{1}{t^{3}+1} d t$$
Step 1
Step 1: The function $g(x)$ is given as an integral from a constant (1) to $x$ of a function $f(t)$, where $f(t) = \frac{1}{t^{3}+1}$. Show more…
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