Use Part 1 of the Fundamental Theorem of Calculus to find the derivative of the function. $$g(x)=\int_{1}^{x} \frac{1}{t^{3}+1} d t$$
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It states that if a function f is continuous over the interval [a, b] and F is an antiderivative of f on [a, b], then the derivative of the function G(x) = ∫[a to x] f(t) dt is G'(x) = f(x). Show more…
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