First, let's recall the formula for the associated Legendre polynomials:
$$P_{l}^{m}(x)=(-1)^{m} \frac{(l+m) !}{(l-m) !} \frac{1}{2^{l} l !} \frac{d^{l-m}}{d x^{l-m}}\left(x^{2}-1\right)^{l}$$
Now, we need to show that:
$$P_{l}^{m}(x)=(-1)^{m} \frac{(l+m)
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