Question
Use Problem 7 to show that$$P_{t}^{m}(x)=(-1)^{m} \frac{(l+m) !}{(l-m) !} \frac{\left(1-x^{2}\right)^{-m / 2}}{2^{\prime} ! !} \frac{d^{t-m}}{d x^{l-m}}\left(x^{2}-1\right)^{l}$$.
Step 1
Step 1: We start with the given relation: $$ P_{l}^{m}(x)=\frac{1}{2^{l} l !}\left(1-x^{2}\right)^{m / 2} \frac{d^{l+m}}{d x^{l+m}}\left(x^{2}-1\right)^{l} $$ Show more…
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Use Problem 7 to show that $$P_{l}^{m}(x)=(-1)^{m} \frac{(l+m) !}{(l-m) !} \frac{\left(1-x^{2}\right)^{-m / 2}}{2^{l} l !} \frac{d^{l-m}}{d x^{l-m}}\left(x^{2}-1\right)^{l}$$
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