00:02
In this problem, they have to consider the derivative of the graph in function.
00:16
So the value of f -prim at 4 will be the slope of the function f at x is equal to 4.
00:28
So from the graph of f -pron, f -prime of 4 is approximately equal to negative 1.
00:45
So then we can conclude that the slope of the function when x is equal to negative 1, so then we can conclude to 4, the slope m is equal to negative 1.
01:10
For part b, part b, they want us to explain, it's impossible that f of 2 is equal to negative 1.
01:31
The answer is no, because the slope of the tangent line is greater than 2 on the interval 0 comma 2, so then f must increase four units.
02:35
On the interval 0 .2.
03:23
For part c, we are tasked to answer the question is f of 5 minus 4 greater than 0.
03:46
So now, the f prime of 5 is greater than 0, i mean it's less than 0, on the interval 4 and 5.
04:20
So the function will be decreasing on that interval...