00:01
Okay, so we're given this equation right here, g of x equals negative 2x squared plus x divided by x, and we're trying to find a, b, and c.
00:07
So if we can show that the left and right hand limits are the same, then we can figure out the limit at that point.
00:13
So at zero, from the left hand side, it's approaching there, and from the right hand side, it's approaching there.
00:19
So both the left and right hand sides are approaching that y value of one.
00:23
Therefore, the limit at x approaches zero, g of x is one.
00:27
Now using the same logic, we're going to do it as x approaches negative one.
00:32
So we're going to do x approaches negative one, then we're going to do the left, and then we'll check the right.
00:38
Now if we check on the left, we'll notice that it's approaching here, and we're going to the right side, it's approaching there.
00:48
So in conclusion, they're both approaching three.
00:51
Therefore, the limit is x approaches negative one, g of x is three.
00:55
Finally, if we do the left hand side, approach x, as x is approaching to negative two from the left hand side, it's approaching five as the y value.
01:05
Now on the right hand side, as x approaches negative two from the right hand side, it's still also approaching five.
01:12
Therefore, the limit will be five...