The Laplace transform of $y''(t)$ is $s^2Y(s) - sy(0) - y'(0)$, the Laplace transform of $y'(t)$ is $sY(s) - y(0)$, and the Laplace transform of $30e^{-3t}$ is $\frac{30}{s+3}$. Substituting these into the differential equation gives us:
\[s^2Y(s) - sy(0) - y'(0)
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