Question
Use the MO model to determine which of the following has the smallest ionization energy: $\mathrm{N}_{2}, \mathrm{O}_{2}, \mathrm{~N}_{2}^{2-}, \mathrm{N}_{2}^{-}, \mathrm{O}_{2}^{+}$, Explain yourans wer.
Step 1
The bond order can be calculated using the formula: Bond Order = 0.5 * (Number of bonding electrons - Number of anti-bonding electrons). For $\mathrm{N}_{2}$, the bond order is 3. For $\mathrm{O}_{2}$, the bond order is 2. For $\mathrm{N}_{2}^{2-}$, the bond Show more…
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Use the MO model to determine which of the following has the smallest ionization energy: $\mathrm{N}_{2}, \mathrm{O}_{2}, \mathrm{N}_{2}^{2-}, \mathrm{N}_{2}^{-}, \mathrm{O}_{2}^{+} .$ Explain your answer.
Arrange the following from lowest to highest ionization energy: $\mathrm{O}, \mathrm{O}_{2}, \mathrm{O}_{2}^{-}, \mathrm{O}_{2}^{+} .$ Explain your answer.
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