Use the power series
$$\frac{1}{1+x}=\sum_{n=0}^{\infty}(-1)^{n} x^{n}$$
to determine a power series, centered at $0,$ for the function. Identify the interval of convergence.
$$f(x)=\frac{2}{(x+1)^{3}}=\frac{d^{2}}{d x^{2}}\left[\frac{1}{x+1}\right]$$