Question
Use the power series$$\frac{1}{1+x}=\sum_{n=0}^{\infty}(-1)^{n} x^{n}$$to determine a power series, centered at $0,$ for the function. Identify the interval of convergence.$$g(x)=\frac{1}{x^{2}+1}$$
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We want to find a similar power series for the function $\frac{1}{x^{2}+1}$. Show more…
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Use the power series $$\frac{1}{1+x}=\sum_{n=0}^{\infty}(-1)^{n} x^{n}$$ to determine a power series, centered at $0,$ for the function. Identify the interval of convergence. $$f(x)=-\frac{1}{(x+1)^{2}}=\frac{d}{d x}\left[\frac{1}{x+1}\right]$$
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