00:01
Okay, so we have some weak base, which i'll just call x minus, and to that we're going to add some strong acid.
00:10
So these will make the conjugate weak acid.
00:13
Okay.
00:14
And to start with, it looks like we're starting with five x minuses and four h -xs.
00:22
Okay, if you look at your box, you can see that.
00:26
And then what we're going to do is we're going to add two h pluses.
00:29
So it looks like this is our limiting reactant.
00:34
So plus two.
00:37
And then we'll be left with three of our x minus, no h pluses, and six of our h -xes.
00:44
So let's see if we can write that as a box here.
00:48
So we're going to have six h -xes.
00:51
So those are the ones that are made of squares and circles.
00:56
Here's three of them.
00:59
We'll make three more.
01:06
And then we need three molecules of x minus.
01:09
Which are just circles.
01:11
So your box would look like that...