00:01
So continuing on with the topic of thermodynamics, what we're looking at here is the standard ental be changed.
00:07
So given our reaction, we're calculating delta h0, and we calculate that as the sum, the moles, the moles, delta h, naught formation of the reactants.
00:27
So our delta h0 here is 286 kilojoules.
00:37
Then we can calculate our delta g -0.
00:41
Delta -g -0 is the sum of the moles, delta -g of formation of our products, subtract the sum, the moles multiplied by the delta -g formation of our reactants.
00:55
So our delta -g -0 in this instance is 3 to 6 kilojoules.
01:01
So, because we know that delta -g is equal to delta -g -0, add rt, lnq, at equilibrium, delta g and is equal to 0, and q is equal to k...