00:01
In this problem, calculating the relativistic moment of first particle, so let it be pr1, which is equal to m0 v by under root 1 minus v square by c square.
00:13
Simplifying it further, i can write 9 .11, multiplication 10 to the power minus 31 kg, multiplication 2 multiplication 10 to the power 8 meter per second by under root 1 minus 2 multiplication 10 to the power 8 whole square by 3 multiplication 10 to the power 8 whole square.
00:33
So on simplification i get the value as, just look at it carefully, 2 .44 multiplication 10 to the power minus 22 kg meter per second.
00:44
Now calculating the relativistic moment for the second particle.
00:48
So i will write the formula pr2 which is equal to m0 b by under root 1 minus b square by c so just putting the value here, i can write 9 .11 multiplication 10 to the power minus 31 kg, multiplication 2 multiplication 10 to the power 3 meter per second by under root 1 minus 2 multiplication 10 to the power 3 whole square by 3 multiplication 10 to the power 8 whole square.
01:18
On solving it further, finally i get the answer as 1 .8 to 0 multiplication 10 to the power minus 27 kg meter per second.
01:28
Now going forward and calculating the classical moment of first particle.
01:33
So i will use the formula p .c1 is equal to m0b which is equal to 9 .11 multiplication 10 to minus 31, multiplication 2 multiplication 10 to the power 8 which is equal to 1 .822, multiplication 10 to the power minus 22...