00:01
We are given here the balanced chemical equation for the reaction of the decomposition of circoneum iodide.
00:13
The reaction, the equation is as follows.
00:18
Circonium iodide is decomposed into pure circoneum and iodide.
00:31
We need to determine the percent yield if what we know is that we have 45 .0 grams of circone ionide decomposing and producing 5 grams of circconium.
00:56
Therefore, these 5 grams represent the experimental or actual yield.
01:12
Now remember that the percent yield is the experimental yield, which is already given, over the theoretical yield.
01:23
Yield times 100%.
01:29
All we need to do is to find the theoretical yield.
01:34
If we, the two substances that are involved in the question are circoneum iodide and circoneal itself.
01:42
And these are the ones that we want to use to establish the more ratio.
01:46
We have one mole of circone ionide reactive or decomposin to produce one more of circoneoneone.
01:55
Okay? this is a ratio.
02:00
One mold of circoneum iodide to one mold of circoneum.
02:05
But because we're giving grams and we need to find grams, the logical thing is to convert these moles to grams by multiplying by the molar mass of circconium iodide up here and just the atomic weight of circone in the denominator...