Question
Water flowing through a hose with a velocity of 6 $\mathrm{m} / \mathrm{s}$, impacts on a wall. Determine the force exerted on the wall by the water flow. Assume the water does not splash back off the wall.
Step 1
The formula for the area of a circle is given by $A = \frac{\pi}{4}D^2$, where $D$ is the diameter of the hose. Here, the diameter $D$ is given as 0.1 meter. So, the area $A$ is calculated as follows: \[A = \frac{\pi}{4} \times (0.1)^2\] Show more…
Show all steps
Your feedback will help us improve your experience
Ankur S and 93 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A stream of water flowing horizontally with a speed of 15 m/s pushes out of a tube of crosssectional area 10-2 m2 and hits at a vertical wall nearby. What is the force exerted on the wall by the impact of water, assuming that it does not rebound?
A stream of water flowing horizontally with a speed of $15 \mathrm{~m} \mathrm{~s}^{-1}$ gushes out of a tube of cross-sectional area $10^{-2} \mathrm{~m}^{2}$, and hits a vertical wall nearby. What is the force exerted on the wall by the impact of water, assuming it does not rebound?
Determine the resultant force that water exerts on the overhang sea wall along $A B C$. The wall is $2 \mathrm{~m}$ wide.
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD