We can do this by multiplying the original volume of the solution by its molarity.
The number of moles of $\mathrm{Na}_{2} \mathrm{SO}_{4}$ is given by:
\[n = C \times V\]
where \(n\) is the number of moles, \(C\) is the molarity, and \(V\) is the volume.
Show more…