We have shown that $\left[v_{i}, J_{j}\right]=\mathrm{i} \sum_{k} \epsilon_{i j k} v_{k}$ for any operator whose components $v_{i}$ form a vector. The expectation value of this operator relation in any state $|\psi\rangle$ is then $\left\langle\psi\left|\left[v_{i}, J_{j}\right]\right| \psi\right\rangle=\mathrm{i} \sum_{k} \epsilon_{i j k}\left\langle\psi\left|v_{k}\right| \psi\right\rangle .$ Check that with $U(\boldsymbol{\alpha})=\mathrm{e}^{-\mathrm{i} \alpha \cdot \mathrm{J}}$ this relation is consistent under a further rotation $|\psi\rangle \rightarrow\left|\psi^{\prime}\right\rangle=U(\boldsymbol{\alpha})|\psi\rangle$ by evaluating both sides separately.